Eric Nicholas K's answer to Sonia's Junior College 2 H1 Maths Singapore question.
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Good morning Sonia! Here are my workings for this question.
For the area of triangle ABC, we can use any of the different forms
1/2 ab sin C
1/2 ac sin B
1/2 bc sin A
to obtain our resultant perpendicular height, since the simplication will result in the existence of either a x a = 0, b x b = 0 or c x c = 0. In my case, there is that b x b that equates to zero.
Let me know if you need more explanation and I will do my best to explain them again.
For the area of triangle ABC, we can use any of the different forms
1/2 ab sin C
1/2 ac sin B
1/2 bc sin A
to obtain our resultant perpendicular height, since the simplication will result in the existence of either a x a = 0, b x b = 0 or c x c = 0. In my case, there is that b x b that equates to zero.
Let me know if you need more explanation and I will do my best to explain them again.
Date Posted:
4 years ago
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