Eric Nicholas K's answer to Elle's Junior College 1 H2 Maths Singapore question.
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An idea, but you have to be mathematically prepared to deal with the problematic algebraic expressions.
Date Posted:
4 years ago
y/x = 3 √(2a - 1)/(2a + 1)
Since a > ½, 2a > 1
2a + 1 > 2 > 0 and 2a - 1 > 0
So (2a - 1)/(2a + 1) > 0
And hence 3√(2a - 1)/(2a + 1) > 0