Matthias Tan's answer to zoey Lim's Secondary 4 E Maths question.
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b) angle TJL= 180°-93°-26°=61°
Let nearest point be A
sin90°/1800=sin61°/AT
AT=1800sin61°/sin90°
=1574.31m
~1570m
Let nearest point be A
sin90°/1800=sin61°/AT
AT=1800sin61°/sin90°
=1574.31m
~1570m
Date Posted:
7 years ago
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