Muhammad's answer to Tara's Secondary 4 A Maths Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Hope this helps:)
Date Posted:
4 years ago
How did you get the equation of the normal curve?
Gradient of normal × gradient of tangent
= -1
at x=2, gradient of curve is 3.
Gradient of normal will be -1/3.
To find equation of the normal line, use
y=mx+c
1 point you can use to substitute into y=mx+c to get line of normal can be there point of intersection of normal and curve.
In this case that x point is 2.
Y point will be ln(3x-5)
=ln(3(2)-5) =ln1=0
Substitute point (2,0) and m=-1/3 into y=mx+c
0=-1/3 (2) +c
C = 2/3
Therefore, y=-1/3 x+2/3
= -1
at x=2, gradient of curve is 3.
Gradient of normal will be -1/3.
To find equation of the normal line, use
y=mx+c
1 point you can use to substitute into y=mx+c to get line of normal can be there point of intersection of normal and curve.
In this case that x point is 2.
Y point will be ln(3x-5)
=ln(3(2)-5) =ln1=0
Substitute point (2,0) and m=-1/3 into y=mx+c
0=-1/3 (2) +c
C = 2/3
Therefore, y=-1/3 x+2/3
360 Tutoring Program