Muhammad's answer to TY's Secondary 3 A Maths Singapore question.
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Hope this helps:)
Date Posted:
4 years ago
The answer is different from answer key, but it did help me understand it a little more. Thanks!
Guess I got a lot more to learn from:)
Do you mind sharing what the answers were?
Do you mind sharing what the answers were?
Answers for 3rd term is: nC2a^(n-2)b^2x^(6x-n)
For 4th term is: nC3a^(n-3)b^3x^(9-n)
And n=17
For 4th term is: nC3a^(n-3)b^3x^(9-n)
And n=17
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