Eric Nicholas K's answer to lim's Junior College 2 H3 Maths Singapore question.
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Part i, I finally recalled my complex numbers slightly
Date Posted:
5 years ago
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(c - a)e^⅓πi
= ce^⅓πi - ae^⅓πi
= re^(θ + 4/3π+⅓π)i - re^(θ + ⅓π)i
= re^(θ+5/3π)i - (- re^(θ + ⅓π + π)i )
= -re^(θ +5/3π - π)i + re^(θ + 4/3π)i
= -re^(θ + ⅔π)i + c
= c - b