Eric Nicholas K's answer to Sonia's Junior College 1 H2 Maths Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Good evening Sonia! Here are my workings for part c.
Date Posted:
4 years ago
Sonia, I have been pondering about this question for some time and was divided between my original working (same as Sophie's) and my this working.
I decided that Sophie's solution is correct. We cannot use the 470 cm3 figure for the H2 gas in this case (leading to the 0.0392 mol) as the impurity sodium oxide also reacts with the water of dissolution, to form sodium hydroxide which adds on to the overall number of moles of sodium hydroxide present.
Also, I owe you the workings for part c in the graphs question. Give me a few moments to post my workings.
I decided that Sophie's solution is correct. We cannot use the 470 cm3 figure for the H2 gas in this case (leading to the 0.0392 mol) as the impurity sodium oxide also reacts with the water of dissolution, to form sodium hydroxide which adds on to the overall number of moles of sodium hydroxide present.
Also, I owe you the workings for part c in the graphs question. Give me a few moments to post my workings.