Wai Mun's answer to Trump's Secondary 4 Malaysia question.
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Your workings is actually not wrong as u obtained cos x = 0 or cos x = 1.
But u have to reject cos x = 0. This is because sec x = 1/cos x and for
sec x and sec^2 x to be defined, cos x cannot be 0.
Hope this helps and I have provided an alternative approach to solving this using the trigonometric Pythagorean identities.
But u have to reject cos x = 0. This is because sec x = 1/cos x and for
sec x and sec^2 x to be defined, cos x cannot be 0.
Hope this helps and I have provided an alternative approach to solving this using the trigonometric Pythagorean identities.
Date Posted:
4 years ago
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