Eric Nicholas K's answer to Annela's Secondary 4 E Maths Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Good evening Annela! Here are my workings for Q17a.
Date Posted:
5 years ago
Hi why is hpn3 =270 degrees?
Good evening Annela! Because P is due east of H, N1HP= 90 degrees.
This means that normal angle HPN3 is 180 - N1HP = 180 - 90 = 90, since both “norths” N1 and N3 are parallel to each other.
Then, reflex HPN3 = 360 - normal HPN3 = 360 - 90 = 270.
I will look at the rest later because I am on the move the whole day with students and other things.
This means that normal angle HPN3 is 180 - N1HP = 180 - 90 = 90, since both “norths” N1 and N3 are parallel to each other.
Then, reflex HPN3 = 360 - normal HPN3 = 360 - 90 = 270.
I will look at the rest later because I am on the move the whole day with students and other things.
The graph questions I will look at it again today but at a very late time, but I will need to find my own graph papers first; alternatively you can use Desmos online graphing calculator or data points plotter (for best fit curves and lines, suitable for linear law as well) to attempt the graph questions.