Eric Nicholas K's answer to Sonia's Secondary 4 A Maths Singapore question.
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Good evening Sonia!!!
For this curve, at your level, you will only be required to sketch graphs of y = a sin bx + c and y = a cos bx + c, rather than y = a sin (bx + c) + d or y = a cos (bx + c) + d.
As such, for graphs starting at the centre point from the y-axis, it would be a sine curve. Specifically, we have a positive sine curve if the curve goes up first and a negative sine curve if the curve goes down first.
For graphs starting at the maximum point from the y-axis (heading downwards), it would be a positive cosine curve. For graphs starting at the minimum point from the y-axis (heading upwards), it would be a negative cosine curve.
Let me know if you need more explanation and I will do my best to explain them again!
For this curve, at your level, you will only be required to sketch graphs of y = a sin bx + c and y = a cos bx + c, rather than y = a sin (bx + c) + d or y = a cos (bx + c) + d.
As such, for graphs starting at the centre point from the y-axis, it would be a sine curve. Specifically, we have a positive sine curve if the curve goes up first and a negative sine curve if the curve goes down first.
For graphs starting at the maximum point from the y-axis (heading downwards), it would be a positive cosine curve. For graphs starting at the minimum point from the y-axis (heading upwards), it would be a negative cosine curve.
Let me know if you need more explanation and I will do my best to explain them again!
Date Posted:
4 years ago
Makes me wonder if 2sin(x/4 + ½π) would be marked correct by Cambridge
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