Agnes Tung's answer to Joneth Santorcas's Primary 6 Maths Speed Singapore question.
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Let d be the distance from school to library.
Ben's speed - Alan's speed = 90
d/20-d/30=90
3d - 2d=5400
d=5400
Alan's speed =5400/30=180 m/min
Ben's speed - Alan's speed = 90
d/20-d/30=90
3d - 2d=5400
d=5400
Alan's speed =5400/30=180 m/min
Date Posted:
4 years ago
Hi , are we able to use simulataneous method
Hi. Yes. You can let x and y be the speeds. The first equation 20x=30y and second equation x-y=90 then solve for x and y.
Thank you so much
Thank you
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