Eric Nicholas K's answer to TitusLim's Secondary 3 E Maths Singapore question.
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The first mixture contains V cm3 vinegar out of the 400 cm3 solution. The proportion of vinegar in this mixture is V/400.
Extracting V cm3 out the solution means extracting out V cm3 of liquid out of the solution with concentration V / 400.
Amount of vinegar taken out this time is V/400 times V = V2 / 400.
New amount of V at the end is (V - V2 / 400) plus the final addition of V, for a grand total of 2V - V2 / 400 cm3 of vinegar in the 400 cm3 mixture.
Extracting V cm3 out the solution means extracting out V cm3 of liquid out of the solution with concentration V / 400.
Amount of vinegar taken out this time is V/400 times V = V2 / 400.
New amount of V at the end is (V - V2 / 400) plus the final addition of V, for a grand total of 2V - V2 / 400 cm3 of vinegar in the 400 cm3 mixture.
Date Posted:
4 years ago
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