AC Lim's answer to Gens's Primary 6 Maths Fractions Singapore question.
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Let Keon = 4u
Tom = 4u+36
Leela= u + 9 (divide 4 from Tom)
Total = 9u + 45
9u + 45 = 315
9u = 270
1u= 30
Keon = 4 x 30 = 120
Leela= 30+9=39
120-39= 81
Keon have 81 more than leela.
Tom = 4u+36
Leela= u + 9 (divide 4 from Tom)
Total = 9u + 45
9u + 45 = 315
9u = 270
1u= 30
Keon = 4 x 30 = 120
Leela= 30+9=39
120-39= 81
Keon have 81 more than leela.
Date Posted:
5 years ago
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