J's answer to Michelle's Primary 6 Maths Speed Singapore question.
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Since they meet every 4 min,
21min ÷ 4min = 5 R 1min
They would have met for 5 times in total
4(1st time) + 4(2nd time) + 4(3rd time) + 4 (4th time) + 4(5th time) + 1min(not met yet) = 21
Since question asks for how many times did they meet again, this means after the first time, they met again for 4 times.
21min ÷ 4min = 5 R 1min
They would have met for 5 times in total
4(1st time) + 4(2nd time) + 4(3rd time) + 4 (4th time) + 4(5th time) + 1min(not met yet) = 21
Since question asks for how many times did they meet again, this means after the first time, they met again for 4 times.
Date Posted:
4 years ago
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