AC Lim's answer to Anis's Primary 5 Maths Percentage Singapore question.
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Zul 50% = Leroy 60%
Zul 1/2 = Leroy 3/5
Zul 3/6 = Leroy 3/5
Therefore Zul have 6u and Leroy have 5u
Total =11u
11u = 165
1u= 15
Leroy have 5u
= 5 x 15
= 75 coins
Zul 1/2 = Leroy 3/5
Zul 3/6 = Leroy 3/5
Therefore Zul have 6u and Leroy have 5u
Total =11u
11u = 165
1u= 15
Leroy have 5u
= 5 x 15
= 75 coins
Date Posted:
4 years ago
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