Eric Nicholas K's answer to Puay Xin yue's Secondary 3 E Maths Singapore question.

done {{ upvoteCount }} Upvotes
clear {{ downvoteCount * -1 }} Downvotes
Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
There are several ways of doing part ii. One way to do this. Another way is to do the A Maths technique of Gauss' area formula, more commonly known as the shoelace method. There are others too, but less obvious.

The third part is to recognise that the area of the same triangle can be viewed from yet a different angle, this time viewing BC as the base and AF as the perpendicular height to BC.