Eric Nicholas K's answer to Kathy's Secondary 4 A Maths Singapore question.
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Q11
As usual, not necessary to show that it is a minimum, but to show it, we just do d2y/dx2, which gets you 4e^2t + 8e^-2t which is clearly more than zero since e^x > 0 for any x and the coefficients 4 and 8 are positive.
As usual, not necessary to show that it is a minimum, but to show it, we just do d2y/dx2, which gets you 4e^2t + 8e^-2t which is clearly more than zero since e^x > 0 for any x and the coefficients 4 and 8 are positive.
Date Posted:
4 years ago
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