Jiayang's answer to Rae Kuan's Secondary 4 A Maths Singapore question.
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Actually I didn't need your pic I was under the impression that you haven't learned calculus.
About part iv, I forgot about one more condition which is the radii must be equal also.
About part iv, I forgot about one more condition which is the radii must be equal also.
Date Posted:
4 years ago
thanks a lot :)
Another way to get the equation of the perpendicular bisector :
Equation of circle is (x - h)² + (y - k)² = r²
Substitute (4,2) and (10,8)
(4 - h)² + (2 - k)² = r²
(10 - h)² + (8 - k)² = r²
So (4 - h)² + (2 - k)² = (10 - h)² + (8 - k)² = r²
16 - 8h + h² + 4 - 4k + k² = 100 - 20h + h² + 64 - 16k + k²
12h + 12k = 144
h + k = 12
k = 12 - h
Let k = y and h = x,
y = 12 - x
This is the equation of the perpendicular bisector, which passes through the centre (h,k)
Equation of circle is (x - h)² + (y - k)² = r²
Substitute (4,2) and (10,8)
(4 - h)² + (2 - k)² = r²
(10 - h)² + (8 - k)² = r²
So (4 - h)² + (2 - k)² = (10 - h)² + (8 - k)² = r²
16 - 8h + h² + 4 - 4k + k² = 100 - 20h + h² + 64 - 16k + k²
12h + 12k = 144
h + k = 12
k = 12 - h
Let k = y and h = x,
y = 12 - x
This is the equation of the perpendicular bisector, which passes through the centre (h,k)
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