Christal's answer to Chelsia's Secondary 3 A Maths Singapore question.

done {{ upvoteCount }} Upvotes
clear {{ downvoteCount * -1 }} Downvotes
Christal
Christal's answer
5 answers (Tutor Details)
1st
for the first equation, use lgA - lgB = lg (A/B)
for the second equation, change the equation to its exponential form ie logxY=a is also Y=x^a