Eric Nicholas K's answer to Georgia Jansen's Secondary 3 A Maths Singapore question.
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Careful with the naming of the roots.
For the given equation, the sum of roots is -b/a and the product of roots is c/a.
But the roots are given as a2 and 6/a, not your typical a and b, so the sum of roots is also equal to a2 + 6/a, not a + b. In other words, a2 + 6/a = “-b/a”.
For the given equation, the sum of roots is -b/a and the product of roots is c/a.
But the roots are given as a2 and 6/a, not your typical a and b, so the sum of roots is also equal to a2 + 6/a, not a + b. In other words, a2 + 6/a = “-b/a”.
Date Posted:
5 years ago
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