Isaac Solomon Wong's answer to Yos's Secondary 4 E Maths Singapore question.
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For a), use trigo and 1/2x(a)x(b)xsinC
For b), the shortest distance between any two points is the perpendicular distance, so by dividing the triangle's area by 1/2 and its base, you get its height, aka the shortest distance.
Use cosine rule for c), pythagores and sine rule for d).
Have fun doing maths buddy :)
For b), the shortest distance between any two points is the perpendicular distance, so by dividing the triangle's area by 1/2 and its base, you get its height, aka the shortest distance.
Use cosine rule for c), pythagores and sine rule for d).
Have fun doing maths buddy :)
Date Posted:
5 years ago
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