snell's answer to Christmas MT's Secondary 4 A Maths Singapore question.
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first off, to figure this qn out,
u read the 1st sentence in the qn.
*usually the first sentence of math qn gives u the clue/hint on how to start
then u hv to recall the angles properties of triangle
(all of them , if u can)
then trigo identities ...
and the rest is history
hope this helps.
u read the 1st sentence in the qn.
*usually the first sentence of math qn gives u the clue/hint on how to start
then u hv to recall the angles properties of triangle
(all of them , if u can)
then trigo identities ...
and the rest is history
hope this helps.
Date Posted:
5 years ago
I got the first 3 lines but why at the fourth line tan C = tan (180 - (A+B) , why tangent 180 - (A+ B)
Omg thanks
u r referring to
C = 180 - (A+B) ? (3rd line)
or
tan C = tan [180 - (A+B)] ? (4th line)
if u hv established
C = 180 - (A+B)
so u wld know tan C, right?
C = 180 - (A+B) ? (3rd line)
or
tan C = tan [180 - (A+B)] ? (4th line)
if u hv established
C = 180 - (A+B)
so u wld know tan C, right?
Yea I got it (the deleted comment) tq it was v well explained
np
i see u replied to XP
who posed his/her qn,
and this allows u to clear his/her doubts in the quickest way.
good job!
i see u replied to XP
who posed his/her qn,
and this allows u to clear his/her doubts in the quickest way.
good job!
erhmm,..
u still need to place the trigo identities list beside when u attempt these trigo qns.
u still need to place the trigo identities list beside when u attempt these trigo qns.
Oh hahah okay
yea I still need to do that
I memorised some (got used to it) but most of them I didn’t
oh u mean the deleted comment?
so u din see the complicated step as one of the trigo identities?
no worries, if u cannot handle 3 variables at one go, just
let A+B be E or something else
then
C = 180 - E
and
tan C = tan (180-E) and solve from here
so u din see the complicated step as one of the trigo identities?
no worries, if u cannot handle 3 variables at one go, just
let A+B be E or something else
then
C = 180 - E
and
tan C = tan (180-E) and solve from here
Yea that works too lol thxx !