Dave Tan Kai Hon's answer to meltedsoups's Secondary 1 Maths Singapore question.
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For this question, as it has to be a perfect square, 3675n has to have all its broken down prime numbers in double powers.
For example,
5^2 x 7^2 is a perfect square.
2^4 is a perfect square.
Thus,for 3675n to be a perfect square, n must make 3675n such that the powers a re all in double figures. Since 3675 allr has 5^2 and 7^2, but the 3 is only of power 1, smallest integer value of n is such that it makes this 3 have a double power.
Hence, n=3.
For example,
5^2 x 7^2 is a perfect square.
2^4 is a perfect square.
Thus,for 3675n to be a perfect square, n must make 3675n such that the powers a re all in double figures. Since 3675 allr has 5^2 and 7^2, but the 3 is only of power 1, smallest integer value of n is such that it makes this 3 have a double power.
Hence, n=3.
Date Posted:
5 years ago
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