Dave Tan Kai Hon's answer to Raphael's Secondary 2 Maths Singapore question.
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Hi! Basically you can choose either 1 of your answers for sinA, cosA or tanA. Using that value, you then take the inverse of the trigonometry function to get A.
E.g. SinA = 3/5, so A = sin-1(3/5)
Using either one of the trigonometry functions, you will then realise that you'll end up with the same answer of 53.1.
E.g. SinA = 3/5, so A = sin-1(3/5)
Using either one of the trigonometry functions, you will then realise that you'll end up with the same answer of 53.1.
Date Posted:
5 years ago
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