Mak, Ivan's answer to Mandy's Primary 5 Maths Angles & Geometry Singapore question.
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Triangle BCD is an isosceles, that means that BC = CD and ∠DBC = ∠BDC only!
We know that triangle ACB is an equilateral triangle, i.e. AB= AC= BC and triangle BCD is an isosceles triangle, i.e. BC=CD.
Hence we know that AC = CD. That is, ACD is an isosceles triangle (triangle with two equal sides is ALWAYS an isosceles). i.e. ∠DAC = ∠ADC = 53 degrees.
Hence ∠ACD = 180-53-53=74 degrees.
∠DBC = BDC = (180-60-74)/2=23 degrees.
I have mathematical proofing for my answer. Can you show proof for your answer?