Anony's answer to Danielle's Secondary 4 E Maths Singapore question.
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Here I hope this helps :D (if you are unsure of any of the rules, search it up or look at your book or you can ask me etc.)
Date Posted:
6 years ago
Alternatively, the angle at centre = twice angle at circumference can also be applied in which since angle CBE = x, angle EOD = 2x. After that you can equate angle DEO + angle BDO + angle EOD = 180 because EOD is a triangle
thank u so much!!
np :D
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