Tan Kee Lin's answer to Tina sari's Primary 5 Maths question.
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(a) J:C:M
=2:3:6
2u=J
1u=1/2J
6u=3J
3J=48+J
J=24
3u=3/2J
=36
Ans:36
(b) 36+14
=50
6u=3J
=72
50/(24+36+72)
=50/132
=25/66
Ans:25/66
=2:3:6
2u=J
1u=1/2J
6u=3J
3J=48+J
J=24
3u=3/2J
=36
Ans:36
(b) 36+14
=50
6u=3J
=72
50/(24+36+72)
=50/132
=25/66
Ans:25/66
Date Posted:
6 years ago
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