Liu Rijing's answer to Shashasre's Junior College 1 H2 Maths question.
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This is conditional probability.
To find this obtain Probability of three winners from X and one winner from Z divided that three winners are from X
P(3X and Z) = 4*200/430*199/429*198/428*150/427
P(Three winners from X)= answer in part a
Hence P(3X and Z/3X)= 150/230=15/23
To find this obtain Probability of three winners from X and one winner from Z divided that three winners are from X
P(3X and Z) = 4*200/430*199/429*198/428*150/427
P(Three winners from X)= answer in part a
Hence P(3X and Z/3X)= 150/230=15/23
Date Posted:
6 years ago
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