Liu Rijing's answer to Shashasre's Junior College 1 H2 Maths question.
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Probability of one combination (XXXYor Z)=200/430*199/429*198/428*230/427
There are 4 possible such combinations.
Hence probability of three winners from X will be = 4*200/430*199/429*198/428*230/427
There are 4 possible such combinations.
Hence probability of three winners from X will be = 4*200/430*199/429*198/428*230/427
Date Posted:
6 years ago
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