Jiayang's answer to Chowder's Junior College 1 H1 Maths question.
For g how do u get = e^x? Can explain
How do u change 1 to bexome e^x . If u bring it from the left handside to the rhs theres 2 e^-x ? How come it become one and positve
Multiply thoughout by e^x.
From your laws of indices:
e^x * e^-x = e^(x-x) = e^0 = 1
From your laws of indices:
e^x * e^-x = e^(x-x) = e^0 = 1
Wait but you didnt get 1 u get e^x ? I cannot understand liao Can explain ols
e^x * 1 = e^x
e^x * (e^-x)(dy/dx) = dy/dx
e^x * (e^-x)y = y
Because e^x * e^-x = e^(x-x) = e^0 = 1
e^x * (e^-x)(dy/dx) = dy/dx
e^x * (e^-x)y = y
Because e^x * e^-x = e^(x-x) = e^0 = 1
What dors the 2nd and 3rd line refers to
The 2nd line of my working, like what's happening on the LHS.
Can u check for me my ans for h pls
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