Tang Jiacheng's answer to Ng Wei Lin's Junior College 1 H2 Maths question.
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The mechinism I have here is probably not correct. The actual mechanism may involve multiple steps/intermediates for example, but the idea is that Br is acting as a nucleophile and attacking the delta positive H atom attached to N, so it is a nucleophilic substitution (Br substituting H).
For the second question, B is the iodoform test, which works for most alcohols which have a methyl group attached to the carbon bonded to OH. It should be clear that phenol cannot give a positive result.
For the second question, B is the iodoform test, which works for most alcohols which have a methyl group attached to the carbon bonded to OH. It should be clear that phenol cannot give a positive result.
Date Posted:
6 years ago
I still dn get how the N can go from the left side of the milecule to the middle at the product!
And iodoform test can also be used on carbonyl compound i tot?
And iodoform test can also be used on carbonyl compound i tot?
Yes, but look carefully, the CO in paraceutamol is not a carbonyl group, but an amide right?
Oh it can only work of the R grp only contains carbon ??
I mean the compound does not even have a carbonyl group. It is an amide group instead (R-CONH-R')...
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