Tan Kee Lin's answer to TheFame's Secondary 4 A Maths question.
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i) mode= number of hours with the most number of workers=10
ii) median=middle value
Total number of workers= 50+120+55+46+29=300
median= value at the 150th worker
=10
iii) mean= average value=
8*50+10*120+13*5515*46+20*29
=11.95
iv) standard deviation =
square root of ( (sum of (x-u)) /N)
=3.466
ii) median=middle value
Total number of workers= 50+120+55+46+29=300
median= value at the 150th worker
=10
iii) mean= average value=
8*50+10*120+13*5515*46+20*29
=11.95
iv) standard deviation =
square root of ( (sum of (x-u)) /N)
=3.466
Date Posted:
6 years ago
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