Tan Kee Lin's answer to umbrella's Secondary 1 Maths question.
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1000=2*2*2*5*5*5
The possible factors of 10000, diamond are 2,2*2,2*2*2,2*2*2*5,2*2*2*5*5,2*2*2*5*5,2*2*2*5*5*5,2*5,2*2*5,2*2*2*5,2*2*2*5*5,2*5*5,2*5*5*5.
You find that for the above factors, only 20,40,50 will yield a 2-digit whole number upon division.
The combinations are (20,50),(40,25) and (50,20).
(20,50) because 1000/20=50. Similarly for the rest.
The possible factors of 10000, diamond are 2,2*2,2*2*2,2*2*2*5,2*2*2*5*5,2*2*2*5*5,2*2*2*5*5*5,2*5,2*2*5,2*2*2*5,2*2*2*5*5,2*5*5,2*5*5*5.
You find that for the above factors, only 20,40,50 will yield a 2-digit whole number upon division.
The combinations are (20,50),(40,25) and (50,20).
(20,50) because 1000/20=50. Similarly for the rest.
Date Posted:
6 years ago
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