Eugene See's answer to Joy's Secondary 3 A Maths question.

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Eugene See
Eugene See's answer
309 answers (Tutor Details)
1st
For the first part, you can either solve for the equation and then work out the sum OR you can manipulate the equation into product of roots & sum of roots

For the second part, I supposed you have to substitute the value of a and then press calculator to show that LHS=RHS