Ann's answer to Milky06's Secondary 4 A Maths question.
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The key is DM=CN=1/2 *8=4
so AN=4[3], BM=[6^2-4^2]=[20]=2[5]
CD=MN=8+6-4[3]-2[5]=14-4[3]-2[5]
where[] is quare root.
so AN=4[3], BM=[6^2-4^2]=[20]=2[5]
CD=MN=8+6-4[3]-2[5]=14-4[3]-2[5]
where[] is quare root.
Date Posted:
6 years ago
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