Icyst's answer to Shruti Chaurasia's Secondary 4 A Maths question.
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Hi Shruti, I guess you just need help with the showing part. A bit tricky but it uses the concept of sin(90-A) = cosA and cos(90-A) = sinA. I hope you know how to solve for the angles in the back part of the question. In exam, if you can't show the first part, remember to continue doing the question!:)
Date Posted:
7 years ago
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