See Jiayang's answer to Donna Armour's Secondary 4 A Maths question

Jiayang's answer to Donna Armour's Secondary 4 A Maths question.

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Date Posted: 7 years ago

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Donna Armour

7 years ago

Thanks for the answer. When working out the distance MN where did the 60 come from in the equation ½(0-60÷−12) (60)

Jiayang

7 years ago

60 is my v₀ (initial speed) which I have already found. -12 is my acceleration. (final velocity - initial velocity)/time = acceleration. So from this eqn I made time the subject to get (0-60)/(-12)