Tham KY's answer to Nur's Junior College 1 H3 Maths question.
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Date Posted:
7 years ago
Thanks....but I want to ask you.....can I use (surd3(8-16x))^3=(surd3(0.6))^3
To find x
You should use the one that needs expansion to find x, exclude the multiplier.
(1-2x) is used in expansion, not (8-16x).
So, should be 1-2x=0.6, not 8-16x=0.6
(1-2x) is used in expansion, not (8-16x).
So, should be 1-2x=0.6, not 8-16x=0.6
Got it.......thanks a lot .......have a nice day....