Mark Yeo's answer to JO's Primary 5 Maths question.
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Hope this helps.
Date Posted:
7 years ago
Thank U so much. Answer is correct. Now I need to digest and transform into models for my kid.
Thanks.
Thanks.
This is a question that requires higher ability understanding of averages. Is your son in GEP or attempting math Olympiad?
None. It’s juz an extract from assessment book.
Cool. Good assessment book. :)
Haaa. Thanks for your help.
Sorry I didn't write more yesterday as it was late. I explained it this way to my son previously. Hope this helps.
The old group average is 154cm. Assuming u add children who are at the average height (154cm) the new group average won't increase.
The old group average is 154cm. Assuming u add children who are at the average height (154cm) the new group average won't increase.
In this case the 3 new children brought in a total of 16cm increment over the old average. This resulted in an increase in overall average from 154 to 156 ie 2cm.
This incremental 16cm needs to be "shared" among the collective group in order to increase the group average.
Hence 16 / 2 equals 8 members in the group.
This incremental 16cm needs to be "shared" among the collective group in order to increase the group average.
Hence 16 / 2 equals 8 members in the group.
No problem. I understand your workings last night. 1 of my mistake when I attempted was using difference of 0.02m instead of 2cm.