Tham KY's answer to Jennifer's Junior College 2 H2 Maths question.
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Date Posted:
6 years ago
Thanks! Do u lnow why my method of treating P as 2R and Q as R/3 cannot work?
Because resistance is inversely proportional to cross sectional area, which uses square of the radius or square of half the diameter. You used just the linear quantity of the diameter, you need to square it.
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