A3ium's answer to Aimanhakim's Secondary 2 Maths question.
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ABCD is similar to PQRX
X=Angle CDA(corr.angles of similar polygons)
=52 degrees
PQ/AB=QR/BC(Ratio of corr.sides of similar polygons)
3.5/7=y/3
7y=10.5
Y=1.5
X=Angle CDA(corr.angles of similar polygons)
=52 degrees
PQ/AB=QR/BC(Ratio of corr.sides of similar polygons)
3.5/7=y/3
7y=10.5
Y=1.5
Date Posted:
7 years ago
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