Shawn's answer to M's Primary 6 Maths Fractions Singapore question.
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A gave 1/5 of A to B and 3/8 of A to C. Note that it is both of total A and not remainder.
Total A gave away —> 1/5 + 3/8 = 23/40
A left —> 40 - 23 = 17u
17u = 3298
At the end all have 17u
1u = 3298/17 = 194
B received 1/5 of A = 8/40 of A
B at first —> 17 - 8 = 9u
9u = 9 x 194 = 1746
Total A gave away —> 1/5 + 3/8 = 23/40
A left —> 40 - 23 = 17u
17u = 3298
At the end all have 17u
1u = 3298/17 = 194
B received 1/5 of A = 8/40 of A
B at first —> 17 - 8 = 9u
9u = 9 x 194 = 1746
Date Posted:
1 month ago
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