AC Lim's answer to Crystal Ang's Primary 6 Maths Ratio Singapore question.
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Explanation. Hope this helps
Date Posted:
5 months ago
Never thought of drawing the lines to have clearer picture . Thank you so much
And in fact, it can show that area of A+B = ½×Length × breath.
Let the height for triangle B = u
Then height for A= Breadth -u
So area A = ½ × Length × (Breadth -u)
Area B = ½ × Length × (u)
Therefore, A+B
= ½ × Length × (Breadth -u) + ½ × Length × (Breadth -u)
= ½ × Length × (Breadth -u +u)
= ½ × Length × (Breadth)
= ½ × (rectangle's area)
Since A+B is half of rectangle, then C+D is another half. Which is another 56.
But a bit difficult to explain to primary student,
Let the height for triangle B = u
Then height for A= Breadth -u
So area A = ½ × Length × (Breadth -u)
Area B = ½ × Length × (u)
Therefore, A+B
= ½ × Length × (Breadth -u) + ½ × Length × (Breadth -u)
= ½ × Length × (Breadth -u +u)
= ½ × Length × (Breadth)
= ½ × (rectangle's area)
Since A+B is half of rectangle, then C+D is another half. Which is another 56.
But a bit difficult to explain to primary student,