Tayng's answer to Vincent Lim's Secondary 4 A Maths Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
I think
Date Posted:
2 months ago
why "negative"?
d/dx [sin(2kx)] = k ⋅ [ -cos(2kx) ] ⋅ 2k
d/dx [sin(2kx)] = k ⋅ [ -cos(2kx) ] ⋅ 2k
Ohhhhhhhhhh oops
360 Tutoring Program