Joshua Thomas Viray Rodrigo's answer to Alex's Secondary 3 A Maths Singapore question.
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Obtain an equation for the discriminant,
then show that discriminant >or= 0 by completing the square
for part ii), any value that is not 2/3 (or 12/18 in my working) is ok, since
for more than one real root,
Discriminant must be > 0 (cannot = 0)
then show that discriminant >or= 0 by completing the square
for part ii), any value that is not 2/3 (or 12/18 in my working) is ok, since
for more than one real root,
Discriminant must be > 0 (cannot = 0)
Date Posted:
8 months ago
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