Wahida's answer to M's Primary 6 Maths Measurement Singapore question.
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2y+15 = 4+4+4+4+BC+ED
2y+15 = 16+BC+ED
BC+ED = 2y+15-16
BC+ED = 2y-1 cm
perimeter of bcde when y=3
BCDE = BC+ED+4+4
BCDE = 2y-1+8
BCDE = 2y+7
BCDE = 6+7
BCDE = 13cm
2y+15 = 16+BC+ED
BC+ED = 2y+15-16
BC+ED = 2y-1 cm
perimeter of bcde when y=3
BCDE = BC+ED+4+4
BCDE = 2y-1+8
BCDE = 2y+7
BCDE = 6+7
BCDE = 13cm
Date Posted:
1 year ago
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