Janell's answer to mary's Secondary 3 A Maths Singapore question.
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b) lg2 - 200= lg (2/200) = lg (1/100)= -2
d) ln e^1/2 - ln e^-1 = ln (e^1/2 / e ^-1) = ln e^3/2 =3/2
d)2lg 30 - 5 - lg9
= lg 900 - lg 9 -5
= lg (900/9) - 5
= lg 10^2 -5
=-3
d) ln e^1/2 - ln e^-1 = ln (e^1/2 / e ^-1) = ln e^3/2 =3/2
d)2lg 30 - 5 - lg9
= lg 900 - lg 9 -5
= lg (900/9) - 5
= lg 10^2 -5
=-3
Date Posted:
1 year ago
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