Jun Heng's answer to Leyna's Secondary 1 Maths Singapore question.
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a)
220 = 2²×5×11
160 = 2⁵×5
140 = 2²×5×7
Highest common factor = 2²×5 = 20
Time for them to meet again = 20 mins
b)
Time they meet is 1550
C)
Duration between 1530 and 1630 = 60 mins
Number of times they will meet = 60÷20 = 3
220 = 2²×5×11
160 = 2⁵×5
140 = 2²×5×7
Highest common factor = 2²×5 = 20
Time for them to meet again = 20 mins
b)
Time they meet is 1550
C)
Duration between 1530 and 1630 = 60 mins
Number of times they will meet = 60÷20 = 3
Date Posted:
1 year ago
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