Han Muyuan Alex's answer to Drizzq's Primary 5 Maths Fractions Singapore question.
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Lets say Mrs Ang had X amount of money:
1) After spending 1/6X on a ring she will have 5/6X remaining;
2) After spending half of the remaining (5/6X) on a necklace she will have 5/12X remaining;
3) After receiving $1330 from her daughter, her money increased to twice her original amount, which is 2X;
4) Hence 2X = 5/12X + 1330
Subtracting 5/12X from both sides, 19/12X = 1330, hence X (Mrs Angs original amount of money) = 840.
Since she spent Half of her remaining (5/6X) on the necklace, she would have spent 5/12X, hence 5/12 x 840 = 350
Hence she spent $350 on the necklace
1) After spending 1/6X on a ring she will have 5/6X remaining;
2) After spending half of the remaining (5/6X) on a necklace she will have 5/12X remaining;
3) After receiving $1330 from her daughter, her money increased to twice her original amount, which is 2X;
4) Hence 2X = 5/12X + 1330
Subtracting 5/12X from both sides, 19/12X = 1330, hence X (Mrs Angs original amount of money) = 840.
Since she spent Half of her remaining (5/6X) on the necklace, she would have spent 5/12X, hence 5/12 x 840 = 350
Hence she spent $350 on the necklace
Date Posted:
1 year ago
Thank you Alex.