Kai Chew's answer to Help's Secondary 3 E Maths Singapore question.
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b) (x-(-p))(x-q)=0
(x+p)(x-q) = 0
x^2 + px -qx -pq= 0
x^2 + (p-q)x - pq = 0
b = p-q
c = -pq
(x+p)(x-q) = 0
x^2 + px -qx -pq= 0
x^2 + (p-q)x - pq = 0
b = p-q
c = -pq
Date Posted:
1 year ago
Cannot undertsand how to get to (x-(-p))(x-q)=0
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